Author: David Blackman
Date: 19:13:03 02/28/99
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On February 28, 1999 at 12:32:57, Bruce Moreland wrote: >I am disappointed that this didn't receive any response. The proposal here is >to do a 7-round Swiss (probably with 24 entrants) and use it to determine two >champions. > >Assuming that one program doesn't win both the titles, this means that one of >the other places in the tournament would have to "count". Does anyone know >enough about the Swiss system to know if this is really possible? > >bruce With 24 players, 7 rounds is usually enough to pick a winner in some category, provided that the category winner really is a fair bit better than the others in the category, and the category winner finishes in about the top 5 outright (or bottom 5 outright). If there are several close contenders for the category, or the top of the category finishes near the middle outright, then you will probably have to rely on dodgy tie-break methods. Of course with 24 players and the top 8 or so all of very similar strength, which seems likely, you might not even get a clear winner outright, since even the top entries will likely pick up a few draws, or triangles (A beats B, B beats C, C beats A). To get a feel for this, try simulating a tournament where higher seeds always win against lower seeds. 24 players 7 rounds definately gets a clear outright winner, and fairly likely a clear category winner. Then try 24 players with ratings 2600, 2580, 2560, 2540 so on down to the bottom. Simulate a tournament with random results weighted according to the predictions of ELO tables. Results are a complete mess, with no guarantee of a clear winner, and if there is one, it won't always be 2600.
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