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Subject: Re: CCT8 Update: New entrant

Author: Robert Hyatt

Date: 20:26:28 02/15/06

Go up one level in this thread


On February 15, 2006 at 17:35:06, Peter Kappler wrote:

>On February 15, 2006 at 17:13:54, Robert Hyatt wrote:
>
>>On February 15, 2006 at 16:24:20, Uri Blass wrote:
>>
>>>On February 15, 2006 at 15:18:56, Robert Hyatt wrote:
>>>
>>>>On February 15, 2006 at 13:19:35, George Tsavdaris wrote:
>>>>
>>>>>On February 15, 2006 at 12:59:32, Peter Skinner wrote:
>>>>>
>>>>>>On February 15, 2006 at 12:55:56, Peter Skinner wrote:
>>>>>>
>>>>>>>Hello all,
>>>>>>>
>>>>>>>As promised by Vincent last week, he has entered Diep into CCT8.
>>>>>
>>>>>Nice but what hardware he will use? Any huge one or normal(fast).....?
>>>>>
>>>>> Also is this the most large number of participants for a CCT or there have been
>>>>>and any larger....?
>>>>> I remember very recently Hiarcs and an experimental Junior participating. Did
>>>>>that happen in the last CCT or in another different than CCT tournament.....?
>>>>>
>>>>> Also 9 rounds with so many participants seems a bit short for me. Do you
>>>>>consider increasing the number of rounds.....?
>>>>>
>>>>
>>>>9 rounds is enough to find a clear 1st place for 512 opponents.  :)
>>>
>>>This is correct if one program wins all the games but it will probably not
>>>happen.
>>>
>>>>
>>>>By the time this event ends, the top group will have all played each other.
>>>
>>>I am not sure of it.
>>>In theory it is possible to have 10 winners with 6 out of 9 and in this case it
>>>is clear that they need to beat weaker programs to get more than 4.5 out of 9 so
>>>not every pair of winners played.
>>>
>>>Uri
>>
>>In practice this doesn't happen.  The real problem is that by round 6, the
>>winner is pretty certain, although three games against weaker opponents are
>>left, and there the luck factor often lurks behind a pawn and jumps out to
>>present a surprise and knock one of the top players off.
>>
>
>I have to believe that you're half-kidding here.  Surely you don't believe that
> adding 3 more rounds increases the variance of the final result?
>
>-Peter
>

Yes, it absolutely does.  Simple example:  4 strong programs, 12 weak ones.
after round 1, you have 8 with 1, 8 with 0, the 8 with 1 include the top 4.
After two rounds, the top four have two, the bottom four have 0, and the rest
have 1 (assuming no draws).  after 3 more rounds the top four have played.  What
now for those other 4 rounds?  Other programs?  With the luck factor increasing
variance?


>
>
>
>
>>log2(#players) is a good number of rounds for starters.  one more gives a couple
>>of more top finishers a better final result.  But too many and many of the final
>>rounds are simply meaningless, as we've seen multiple times.  For example, at
>>the last WCCC they tried to fudge the round-robin pairing to put a few of the
>>"interesting games" on the final few rounds.  Didn't work out at all and the
>>event was over early...
>>
>>There can always be too many rounds in a Swiss.
>>
>>9 is on the edge.  Both in final results and in total time required to play 9
>>games...



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