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Subject: Re: Outputting u64 word using printf?

Author: Vincent Diepeveen

Date: 07:36:58 06/07/04

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On June 07, 2004 at 10:30:50, Fabien Letouzey wrote:

>>Like when I tried this,
>
>>void main()
>>{
>>	typedef unsigned __int64 u64;
>>	u64 r;
>>	r=1<<36;
>>	printf("%I64u",r);
>>	getchar();
>>}
>
>>The r value was printed as 0.Also for other numbers >36 its printing as 0.Is
>>this correct value that r is having?
>
>Yes, you shift "1" which is a 32-bit integer (int).
>It should be r = 1ui64 << 36;
>I suppose "1i64u" or "(unsigned __int64) 1" also work.
>
>Fabien.

r = 1<<36; // works for good compilers not for the rest



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