Author: Poschmann
Date: 23:48:18 07/31/00
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On July 31, 2000 at 02:25:37, Poschmann wrote: >In a magazine I found the following position. It should be a draw ? >Unfortunately I don't have the following issue of the magazine with the >solution. >It is a 6-piece-endgame. I tried to solve it with the help of Fritz6 >(without tablebases), but I can't. > >[D]K7/8/4k3/1R1R4/8/8/p7/7r w - - > >I had the following to ideas: >a) Go to a 5-piece-endgame: >1. Re5+ Kf6 2. Rf5+ Kg6 3. Rg5+ Kh6 4. Rh5+ Rxh5 5. Rb6+ Kg5 6. Ra6 Rh2 > >b) Allow Black to promote the pawn: >... 4. Rge5 a1=Q+ 5. Ra5 > >I think in both cases White loses the game. But I can't proof it without >tablebases. >- Can somebody with the 5-piece-tablebases proof position a) >- Are some 6-piece-tablebases available to proof position b) without a pawn or > the initial position with one pawn. >- Is there somebody who knows the initial position and its solution ? > >Thank you >Ralf Poschmann Thank you all ! At first I was very surprised about the very different lines of the computer (crafty + tablebases) and the human. But then it become quite clear. If both lines come to a draw, the computer selects its best. It depends on the number of plies until the draw or if equal on the sorting order of its moves or tablebase entries in memory. But a human player thinks completely different. _NO_ tournament player will make 1. ... Kd6 because this draw is seen immediately. _EVERY_ black player will try to win the position with Kf6 because the position is not so clear. If the computer should play more human like, the programmer needs an algorithmic expression for the different situations after the two moves Kd6 / Kf6. This expression will increase the practical difficulties of his human counterpart. Ralf Poschmann
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