Author: Bob Durrett
Date: 18:53:12 11/10/02
Go up one level in this thread
On November 10, 2002 at 21:50:20, Robert Hyatt wrote: >On November 10, 2002 at 11:07:17, Ricardo Gibert wrote: > >>On November 10, 2002 at 07:40:33, José de Jesús García Ruvalcaba wrote: >> >>>On November 09, 2002 at 15:55:48, Ricardo Gibert wrote: >>> >>>> >>>>9 rounds are too many for the number of participants playing in a swiss. You end >>>>up with weird pairing toward the end of the tournament where a high ranked >>>>program gets paired with some program ranked in the middle, because the high >>>>ranked program has played all the programs ranked higher already. This makes the >>>>last round a bit of an anticlimax. Yuck! >>>> >>>>It makes more sense to play 5 rounds of 2 games each for a total of 10 games. 5 >>>>rounds are perfect for the number of contestants entered and now the pairings >>>>will always make some sense particularly because color allocation will not be a >>>>problem. You will also get more games played between the high ranked programs >>>>which will lend more interest to the contest. >>>> >>>>To me the choice is clear cut. 5 rounds of 2 games each PLEASE! >>> >>>Last time there were like 50 participants (I do not remember the actual number), >>>so five rounds are not enough. >> >>5 rounds at 2 games per round makes 10 games. How can 9 games be enough and 10 >>games not be enough? Do you really expect a big tie for first place, because >>"five rounds are not enough?" > >I assume you are talking about playing an opponent twice, once black and once >white? That means you only have 5 different opponents in an event with >50 players. Not enough to get a valid winner in a swiss event, which needs >at _least_ log2(entries) rounds to really find the "best" player... Assuming no draws? Bob D.
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