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Subject: Re: Why Fritz has to play against FIBIChess (for E.Nemeth)

Author: Amir Ban

Date: 23:23:28 07/08/04

Go up one level in this thread


On July 08, 2004 at 17:06:20, Robert Hyatt wrote:

>On July 08, 2004 at 16:59:07, James Robertson wrote:
>
>>On July 08, 2004 at 16:50:24, Robert Hyatt wrote:
>>
>>>On July 08, 2004 at 16:30:07, Ingo Althofer wrote:
>>>
>>>>On July 08, 2004 at 15:07:14, Anson T J wrote:
>>>>
>>>>>WCCC  2004 Cross Table After Round 6
>>>>>
>>>>>                    1  2  3  4  5  6  7  8  9  0  1  2  3  4
>>>>>1 Deep JuniorEY     *  ½  1  ½        1     1     1             5.0/6
>>>>>2 Shredder          ½  *     ½  1  ½  1     ½                   4.0/6
>>>>>3 Deep Sjeng        0     *     ½  ½     1  ½        1          3.5/6  11.00
>>>>>4 Jonny 2.64        ½  ½     *        ½  0     1        1       3.5/6  10.25
>>>>>5 ParSOS               0  ½     *        ½     ½  1  1          3.5/6  9.75
>>>>>6 Fritz                ½  ½        *     0  1  ½        1       3.5/6  9.50
>>>>>7 Diep              0  0     ½        *  1           1  1       3.5/6  9.25
>>>>>8 Falcon Bar-Ilan         0  1  ½  1  0  *                 1    3.5/6  8.75
>>>>>9 Crafty 19.15      0  ½  ½        0        *  1           1    3.0/6
>>>>>0 ISIChess                   0  ½  ½        0  *  ½        1    2.5/6  4.75
>>>>>1 WoodPusher 1997   0           0              ½  *  ½  ½  1    2.5/6  3.25
>>>>>2 Movei                   0     0     0           ½  *  1  1    2.5/6  2.75
>>>>>3 The Crazy Bishop           0     0  0           ½  0  *  1    1.5/6
>>>>>4 FIBIChess                              0  0  0  0  0  0  *    0.0/6
>>>>
>>>>Thanks for the good presentation.
>>>>
>>>>And now it becomes clear, why Fritz has to play against FIBIChess:
>>>>FIBI has played already against all on ranks 8 to 13... and Fritz is on
>>>>shared rank 3 to 8.
>>>>
>>>>Ingo Althofer.
>>>
>>>
>>>This obviously caused by _way_ too many rounds for 14 participants.  It will
>>>almost end up a round robin, lacking only two games to make that happen...
>>
>>I don't see why this particular pairing is caused by the large number of rounds.
>>If there were only 7 rounds instead of 11, wouldn't the pairings up to this
>>point be exactly the same? Does the pairing program take into account the number
>>of rounds?
>
>No.  The point is that the top programs have _already_ played.  Now all that can
>be done is to pair them down.
>

A glance at the cross-table shows that this is not true. There are still many
games missing among the top 8. E.g. Rank 2 & 3 have not played yet.

Amir



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