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Subject: Re: DB NPS (anyone know the position used)?

Author: Peter W. Gillgasch

Date: 18:55:01 01/25/00

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On January 25, 2000 at 21:21:53, Chris Carson wrote:

>On January 25, 2000 at 20:56:21, Peter W. Gillgasch wrote:
>
>>On January 25, 2000 at 08:46:27, Chris Carson wrote:
>>
>>>Does anyone know what position(s) HSU used
>>>to get the 100M NPS (DB) or 200M NPS for
>>>DBII?
>>
>>Why do you think that the position matters
>>at all ? As long as he can keep the chips
>>busy the total number of cycles should be
>>constant. Since he was doing the last 4 plies
>>in hardware - and that means that he basically
>>did all the positions in hardware - I suspect
>>that the overhead onthe SP which certainly
>>depends on the position can be neglected...
>>Obvious, isn´t it ?
>>
>>-- Peter
>>
>>>Was it one position or many position's?  Was it
>>>middle game, endgame, or combination?
>>>
>>>I would like to have the EPD for the
>>>position, it would be interesting to
>>>benchmark against.  :)
>>>
>>>Thanks.
>>>
>>>Best Regards,
>>>Chris Carson
>
>OK, but that is not why I wanted the position.  HSU
>quoted the numbers and I would like to know what positions
>were used.
>
>Best Regards,
>Chris Carson

Yes I realize that you want to see the position :)

Anyway, I am not sure if you understood my point, though.
I apologize in advance if this is not the case.

Excuse me for being blunt but let me reformulate
my point: the NPS rate of a one by one hardware move
generator that is fed via a general purpose computer
which forks out the last 4 plies is IMHO basically
__constant__, since the frequency of FIND-VICTIM,
FIND-AGGRESSOR, MAKE-MOVE, EVALUATE, UNMAKE-MOVE,
A-B operations is constant and the software overhead
on the SP can be ignored since the tree that is
searched on the SP is (relatively speaking) non
existant.

So my guess is that you can take the starting
position or a pawn ending to time the thing. Doesn´t
matter in terms of nodal rate. Same result.

-- Peter




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