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Subject: Re: Natural move generation with bitboards (was Re:significant math)

Author: Steffan Westcott

Date: 16:17:46 11/21/02

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On November 21, 2002 at 15:23:55, Alessandro Damiani wrote:

>On November 21, 2002 at 06:47:24, Steffan Westcott wrote:
>
>>On November 21, 2002 at 05:55:59, Alessandro Damiani wrote:
>>
>>>And for sliding pieces? The distance between the from- and the to-square is not
>>>fixed. In the worst case, for each to-square there are 7 from-squares for one
>>>direction. Do you keep one bitboard for each distance in one direction, ordered
>>>from 1 to 7? Just my first thought.
>>
>>No, just one bitboard is used to store all possible destination squares for,
>>say, upward rook moves. Look for my example routines FillUpOccluded(),
>>FillRightOccluded(), etc in the CCC archives (when they get updated, eventually
>>:-< ) for a suggestion on how to calculate this type of bitboard quickly.
>>
>
>I already understood the concept with "one bitboard for each direction". Let's
>take a look at the example position I gave in a previous post (here again):
>
>[D]4r1k1/2q2pp1/p1p4p/Pp1b4/1P6/2N1PN2/4QPPP/3R2K1 w - - 0 1
>
>The bitboard for *all bishops right-down* is:
>
>::::::::
>::::::::
>::::::::
>::::::::
>::::#:::
>:::::#::
>::::::::
>::::::::
>
>As you said, each time a move is searched, its to-square is removed from the
>bitboard. We look at the bitboard above as a generic state in the generation
>process (part of the invariant). By knowing the direction "right-down" we start
>at the left-up most bit set to 1, right? Do you keep an additional invariant
>related to the from-square? Or do I like the from-square far too much?? *g*

Alessandro,

Given a bitboard with a single set bit for the move target square and a
(sliding) move direction, finding the source square of the moving piece is
simple. Just make an attack bitboard from the target square going in the
_reverse_ direction (using FillOccludedxxx), then bitwise AND (&) the result
with the 'AllPieces' bitboard. Put succintly, trace the attack back to its
source.

Cheers,
Steffan



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