Author: Robert Hyatt
Date: 11:07:18 05/16/01
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On May 16, 2001 at 13:05:13, J. Wesley Cleveland wrote: >On May 15, 2001 at 22:11:15, Robert Hyatt wrote: > >>On May 15, 2001 at 12:18:43, J. Wesley Cleveland wrote: >> >[snip] > >>>>First, how do you conclude 10^25? assuming alpha/beta and sqrt(N)? >>> >>>It is a classic alpha-beta search with a transposition table large enough to >>>hold *all* positions found in the search. I'm guessing at the number of >>>positions, but I feel that the same logic should hold, as only positions with >>>one side playing perfectly would be seen. >> >>I don't follow. We know that within the 50 move rule, the longest game that >>can be played is something over 10,000 plies. IE 50 moves, then a pawn push >>or capture, then 50 more, etc. Eventually you run out of pieces and it is a >>draw. But 38^10000 and 10^25 seem to have little in common. The alpha/beta >>algorithm is going to search about 38^50000 nodes to search that tree to max >>depth of 10,000. > >Look at it another way. The only positions that are visited by an alpha/beta >search (with perfect move ordering) are those where one side plays perfectly. >The question is what fraction of the total number of positions that is. > The precise formula is: N = W^floor(D/2) + W^ceil(D/2) for all D. floor means round down in integer math, ceil means round up. For the cases where D is even: N = 2 * W^(D/2) which is 2 * sqrt(minimax). If you assume that the total number of positions is roughly 2^168, then you get 2 * sqrt(2^168) or 2 * 2^84. Which is fairly close to the number of atoms in the universe. Note that 168 is not cast in stone either. It might be a few bits more or less, but it is probably close. >> >>Another way of estimating is that somewhere along the way, someone found a >>way to represent a chess position (pieces only) in 168 bits. if you take that >>as an estimate of the total possible positions then you get 2^168 or roughly >>10^165 which is a _huge_ number. > >2^168 = 3.7*10^50 Right. overflow on my calculator tool screwed that up. :)
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